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(G)=2G^2-3G+4
We move all terms to the left:
(G)-(2G^2-3G+4)=0
We get rid of parentheses
-2G^2+G+3G-4=0
We add all the numbers together, and all the variables
-2G^2+4G-4=0
a = -2; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-2)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation
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